(x^2/7)(x^5/2)/(x^-4/5)

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Solution for (x^2/7)(x^5/2)/(x^-4/5) equation: 


D( x )

x = 0

(x^-4)/5 = 0

x = 0

x = 0

(x^-4)/5 = 0

(x^-4)/5 = 0

1/5*x^-4 = 0 // : 1/5

x^-4 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((x^2)/7)*((x^5)/2))/((x^-4)/5) = 0

5/14*x^11 = 0 // : 5/14

x^11 = 0

x = 0

x in { 0} 

x belongs to the empty set

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